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4.9x^2-1.05x-1.4=0
a = 4.9; b = -1.05; c = -1.4;
Δ = b2-4ac
Δ = -1.052-4·4.9·(-1.4)
Δ = 28.5425
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1.05)-\sqrt{28.5425}}{2*4.9}=\frac{1.05-\sqrt{28.5425}}{9.8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1.05)+\sqrt{28.5425}}{2*4.9}=\frac{1.05+\sqrt{28.5425}}{9.8} $
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